Regular Expressions 101

Community Patterns

22

Get path from any text

Created·2023-01-31 14:38
Updated·2023-07-23 20:17
Flavor·PCRE2 (PHP)
Recommended·
Get path (windows style) from any type of text (error message, e-mail corps ...), quoted or not. THIS IS THE SINGLE LINE VERSION ! If you want understand how it work or edit it, go https://regex101.com/r/7o2fyy Relative path are not supported The goal is to catch what "Look like" a path. See the limitations UNC path and prefix path like //./], [//?/] or [//./UNC/] are allowed some url path like [file:///C:/] or [file://] are allowed Catch path quoted with ["] and [']. But these quotes are include with the catch Quoted path is not concerned by limitations Limitations : (only unquoted path) [dot] and [space] is allowed, but not in a row [dot+space] or [space+dot at end of file name isn't catched INSIDE A NAME FILE (or last directory if it is a path to a directory) : [comma] is not supported (it stop the catch) after a first [dot], any [space] stop the catch after a [space], catch is stoped if next character is not a [letter], [digit] or [-] so, double [space] stop the catch Compatibility compatible PCRE, PCRE2 AutoHotkey : don't forget to escape "%" in "`%" /!\ Powershell and .Net /!\\ : this regex need some modification to be interpreted by powershell. You have to replace each (?&CapturGroupName) by \k. Use this powershell code to do this replacement : ` $powershellRegex = @' [Put here the regex to replace (?&CapturGroupName) with \k] '@ -replace '\(\?&(\w+)\)', '\k' ` This example code must return : [Put here the regex to replace \k with \k]
Submitted by nitrateag

Community Library Entry

1

Regular Expression
Created·2022-04-05 14:16
Flavor·JavaScript

/
^(?<domain>[^/?#]+) wants you to sign in with your Ethereum account:\n(?<address>0x[a-zA-Z0-9]{40})\n\n((?<statement>[^\n]+)\n)?\nURI: (?<uri>(([^:?#]+):)?(([^?#]*))?([^?#]*)(\?([^#]*))?(#(.*))??)\nVersion: (?<version>1)\nChain ID: (?<chain_id>[0-9]+)\nNonce: (?<nonce>[a-zA-Z0-9]{8,})\nIssued At: (?<issued_at>([0-9]+)-(0[1-9]|1[012])-(0[1-9]|[12][0-9]|3[01])[Tt]([01][0-9]|2[0-3]):([0-5][0-9]):([0-5][0-9]|60)(\.[0-9]+)?(([Zz])|([+|\-]([01][0-9]|2[0-3]):[0-5][0-9])))(\nExpiration Time: (?<expiration_time>([0-9]+)-(0[1-9]|1[012])-(0[1-9]|[12][0-9]|3[01])[Tt]([01][0-9]|2[0-3]):([0-5][0-9]):([0-5][0-9]|60)(\.[0-9]+)?(([Zz])|([+|\-]([01][0-9]|2[0-3]):[0-5][0-9]))))?(\nNot Before: (?<not_before>([0-9]+)-(0[1-9]|1[012])-(0[1-9]|[12][0-9]|3[01])[Tt]([01][0-9]|2[0-3]):([0-5][0-9]):([0-5][0-9]|60)(\.[0-9]+)?(([Zz])|([+|\-]([01][0-9]|2[0-3]):[0-5][0-9]))))?(\nRequest ID: (?<request_id>[-._~!$&'()*+,;=:@%a-zA-Z0-9]*))?(\nResources:(?<resources>(\n- (([^:?#]+):)?(([^?#]*))?([^?#]*)(\?([^#]*))?(#(.*))??)+))?$
/
g
Open regex in editor

Description

This is the complete Sign-In with Ethereum RegExp implementation

Submitted by anonymous