Regular Expressions 101

Community Patterns

22

Get path from any text

Created·2023-01-31 14:38
Updated·2023-07-23 20:17
Flavor·PCRE2 (PHP)
Recommended·
Get path (windows style) from any type of text (error message, e-mail corps ...), quoted or not. THIS IS THE SINGLE LINE VERSION ! If you want understand how it work or edit it, go https://regex101.com/r/7o2fyy Relative path are not supported The goal is to catch what "Look like" a path. See the limitations UNC path and prefix path like //./], [//?/] or [//./UNC/] are allowed some url path like [file:///C:/] or [file://] are allowed Catch path quoted with ["] and [']. But these quotes are include with the catch Quoted path is not concerned by limitations Limitations : (only unquoted path) [dot] and [space] is allowed, but not in a row [dot+space] or [space+dot at end of file name isn't catched INSIDE A NAME FILE (or last directory if it is a path to a directory) : [comma] is not supported (it stop the catch) after a first [dot], any [space] stop the catch after a [space], catch is stoped if next character is not a [letter], [digit] or [-] so, double [space] stop the catch Compatibility compatible PCRE, PCRE2 AutoHotkey : don't forget to escape "%" in "`%" /!\ Powershell and .Net /!\\ : this regex need some modification to be interpreted by powershell. You have to replace each (?&CapturGroupName) by \k. Use this powershell code to do this replacement : ` $powershellRegex = @' [Put here the regex to replace (?&CapturGroupName) with \k] '@ -replace '\(\?&(\w+)\)', '\k' ` This example code must return : [Put here the regex to replace \k with \k]
Submitted by nitrateag

Community Library Entry

0

Regular Expression
Created·2020-05-28 07:02
Flavor·JavaScript

/
([+\-*\/]{2,}\d+)|(\([+\*\/])|((?<![\d\)])[+\*\/]\()|(\)[+\-\*\/](?![\d\()]))|((?<![\d\)])(?=[+\*\/]\d+))|(\(\))|(\d+[+\-\*\/](?![\d(]))|((?<![\d\+\-\*\/])\([+\-\*\/])|((?<![\d])[+\-\*\/]\))
/
gm
Open regex in editor

Description

校验数学表达式:主要功能如下: 连续的运算符,例如--5 运算符为正数时,其符号+必须省略,例如+2+4定义为非法,而负数时为合法,例如-2+4 前面补零 程序要能处理表达式中间出现的空格(输入表达式中存在空格为合法情况) (后面是运算符 + / * 没数字! )前面是运算符 + - * / 没数字! -) (1 -6)-(-1+2) 010 0 开头的数字 4-

-(9-1) 允许 (9-1)- 不允许 +9+1 不允许 -9+1 允许

Submitted by anonymous