Regular Expressions 101

Community Patterns

21

Get path from any text

Created·2023-01-31 14:38
Updated·2023-07-23 20:17
Flavor·PCRE2 (PHP)
Recommended·
Get path (windows style) from any type of text (error message, e-mail corps ...), quoted or not. THIS IS THE SINGLE LINE VERSION ! If you want understand how it work or edit it, go https://regex101.com/r/7o2fyy Relative path are not supported The goal is to catch what "Look like" a path. See the limitations UNC path and prefix path like //./], [//?/] or [//./UNC/] are allowed some url path like [file:///C:/] or [file://] are allowed Catch path quoted with ["] and [']. But these quotes are include with the catch Quoted path is not concerned by limitations Limitations : (only unquoted path) [dot] and [space] is allowed, but not in a row [dot+space] or [space+dot at end of file name isn't catched INSIDE A NAME FILE (or last directory if it is a path to a directory) : [comma] is not supported (it stop the catch) after a first [dot], any [space] stop the catch after a [space], catch is stoped if next character is not a [letter], [digit] or [-] so, double [space] stop the catch Compatibility compatible PCRE, PCRE2 AutoHotkey : don't forget to escape "%" in "`%" /!\ Powershell and .Net /!\\ : this regex need some modification to be interpreted by powershell. You have to replace each (?&CapturGroupName) by \k. Use this powershell code to do this replacement : ` $powershellRegex = @' [Put here the regex to replace (?&CapturGroupName) with \k] '@ -replace '\(\?&(\w+)\)', '\k' ` This example code must return : [Put here the regex to replace \k with \k]
Submitted by nitrateag

Community Library Entry

1

Regular Expression
Created·2014-02-16 14:11
Flavor·PCRE (Legacy)

/
^ # begin \s*# some empty spaces (?: \+? # + symbol \d{1,2} # country code \s* (?(?=\)) # if followed by parens | # then dash not allowed -? # else optional dash ) )? #prefix like +380 \s* (?: (?P<leftparen>\()? # optional left paren \s* 0\d\d \s* (?(leftparen)\)|) # right paren if and only if left paren )? # operator code, starting with 0, optinally in parentheses (?(?<=\)) # if preceded by parens \s*| # then dash not allowed \s*-?\s* # else optional dash ) (?: \d | (?<= \d ) (?(sep) (?P=sep)| (?P<sep>[\-\/\ ]) ) (?= \d ) ){5,13} \s*# some empty spaces $ # end #\d\d\d (?P<separator>-?) \d\d (?P=separator) \d\d $
/
mgx
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Submitted by Oleksandr Sochka