import Foundation
let pattern = #"^(?:\d{8}(?:\d{2}(?:\d{2})?)?|\(\+?\d{2,3}\)\s?(?:\d{4}[\s*.-]?\d{4}|\d{3}[\s*.-]?\d{3}|\d{2}([\s*.-]?)\d{2}\1\d{2}(?:\1\d{2})?))$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
It can contain open and close parenthesis ex. (55)
It can contin or not '+' char ex. (+52)
It can contain 2 or 3 numbers inside parenthesis ex. (+555) o (+55)
It can contain whitespace between close parenthesis and the next numbers ex. (55) 44332211
The consecutive numbers to the parenthesis must be 6 or 8 numbers ex. (55)443322 o (55)44332211
The consecutive numbers to the parenthesis can contain whitespaces, dashes, asterisks, or colons. ex.(55)44-33-22-11 o (55)44 33 22 11 o (55)44*33*22*11 o (55)44.33.22.11
The consecutive numbers to the parenthesis can be divided in groups of 2, 3 or 4 numbers ex. (55)5544-3322 o (55)55 44 33 22 o (555)444*333
The number format can come in a row of 8, 10 o 12 numbers ex. 55443322 o 5544332211 o 554433221100
(55)test
(55)333-test
(55)test 22
554433221100
5544332211
55443322
(55)443322
(55)44332211
(+55)443322
(+55)44332211
(55)4433*2211
(55)444.333
(55)44-33-22-11
(55)4433-2211
(+55)443 322
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression