import Foundation
let pattern = #"href=[\'\"]?([^\'\" >]+)"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #""<li><a>href=http://w...content-available-to-author-only...f.br/cdara/sisu-2/sisu-2017-1a-edicao/lista-de-espera-sisu-3/?id_curso=01GV&id_grupo=70>ADMINISTRAÇÃO - GOVERNADOR VALADARES - DIURNO - SISU - GRUPO A</a></li><li><a href=http://w...content-available-to-author-only...f.br/cdara/sisu-2/sisu-2017-1a-edicao/lista-de-espera-sisu-3/?id_curso=01GV&id_grupo=71>ADMINISTRAÇÃO - GOVERNADOR VALADARES - DIURNO - SISU - GRUPO B</a></li>""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression