import Foundation
let pattern = #"\b(?:(?:0{2,}(:))+0*|0+\B)"#
let regex = try! NSRegularExpression(pattern: pattern, options: [.anchorsMatchLines, .caseInsensitive])
let testString = #"""
2001:0db8:abcd:0012:0000:0000:0000:0001
2001:0db8:abcd:0012:0000:0000:0000:00a2
2001:0db8:abcd:0012:0000:0000:0000:00ff
a:b:0:c:d:e:f:g
2001:0db8:abcd:0012:0000:0000:0000:0001
:00ff:0000:
0012:0000:0000:0000:0001
0000:0000:0000:0000:0001
0000:0000:1234:0000:0000
0001:0000:0000:0000:0000
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let substitutionString = #"$1"#
let result = regex.stringByReplacingMatches(in: testString, range: stringRange, withTemplate: substitutionString)
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression