re = /^(?:(?:(0?[1-9]|1\d|2[0-8])[\/](0?[1-9]|1[0-2])|(29|30)[\/](0?[13-9]|1[0-2])|(31)[\/](0?[13578]|1[02]))[\/](0{2,3}[1-9]|0{1,2}[1-9]\d|0?[1-9]\d{2}|[1-9]\d{3})|(29)[\/](0?2)[\/](\d{1,2}(?:0[48]|[2468][048]|[13579][26])|(?:0?[48]|[13579][26]|[2468][048])00))$/m
str = '19/6/2003
23/4/2003
25/12/2022
15/7/2026
30/2/2004
32/11/2005
0/5/2001'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html