# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"[^a-zA-Z0-9_,](?:\d{1,3},)*\d{1,3}\.\d\d\b"
test_str = ("Hey Boss: \n\n"
"Just so you know, I did all the crimes. Like 100 of them. So many crimes. \n\n"
"We should probably delete this e-mail before we get sued.\n\n"
"xoxoxo,\n\n"
"Lackey.\n\n\n"
"Crime, INC.\n\n"
"For services rendered: \n\n"
"Tax Fraud 100.00\n\n"
"Price-fixing 9.99\n\n"
"Insider trading 20.00\n\n"
"TOTAL 129.99 \n\n\n"
"Here is a stupid number .00\n\n"
"And here is another stupid number 1,000000,000.00\n\n"
"Dear Boss:\n\n"
"Remember all those crimes I've committed? They made the firm $1,280,012.05. Maybe a raise?\n\n"
"xoxoxo,\n\n"
"Lackey\n\n"
"p.s. Here's a large dollar amount that also would not have matched the previous regex, but will match the new one!: 1,000,000,000,000.00 \n\n")
matches = re.finditer(regex, test_str, re.MULTILINE)
for matchNum, match in enumerate(matches, start=1):
print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))
for groupNum in range(0, len(match.groups())):
groupNum = groupNum + 1
print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html