import Foundation
let pattern = #"^([^0-9]*\b(([1-9]|1[0-9]|22|2[4-9]|[3-9][0-9]|1[0-2][0-9]|13[0-6]|1[4-9][0-9]|[2-9][0-9][0-8]|[1-9][0-9]{3}|[1-5][0-9]{4}|6[0-4][0-9]{3}|65[0-4][0-9]{2}|655[0-2][0-9]|6553[0-5])\b[^0-9]*)*$)"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
56;45;5623;67;21;68
45;568;56564;68;254;136
8080;8958;368;65;80;443;22
8080;22;140
139;852;21;80
65;80;135
65;139
54;98;35;65;2 ;45
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression