import Foundation
// WARNING: You included a flag that Swift doesn't support: U
// When this flag is set, it inverts the "greediness" of the quantifiers so that they are not greedy by default, but become greedy if followed by '?'.
// As an alternative, this effect can also be achieved by setting a (?U) modifier setting within the pattern or by a question mark behind a quantifier (e.g. .*?).
let pattern = #"On\s[a-z]{3},\s[0-9]{1,2}\s[a-z]{3,4}\s[0-9]{4}\sat\s[0-9]{1,2}:[0-9]{1,2},\s[^<]*<[a-z0-9._%+\-]+@[a-z0-9.\-]+\.[a-z]{2,6}>\swrote:"#
let regex = try! NSRegularExpression(pattern: pattern, options: [.anchorsMatchLines, .caseInsensitive])
let testString = #"""
On Thu, 4 Oct 2018 at 10:48, The Rounds <no-reply+dev@therounds.com> wrote:
On Sun, 23 Sept 2018 at 09:01, Some Person <cool_guy-123+extra@a.co.uk> wrote:
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression