re = /(?<=\d{8})((?:0*)(\d{,8}))(?=\d{8})/
str = '112233441234567855667788 --> 12345678
112233440012345655667788 --> 123456
112233001234567855667788 --> 12345678
112233000012345655667788 --> 123456'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html