import Foundation
let pattern = #"^(?:[^,\r\n]*,){6}.*\r?\n(?:[^,\r\n]*,){9}.*(?:\r?\n(?!(?:[^,\r\n]*,){6}.*\r?\n(?:[^,\r\n]*,){9}).*)*"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
LB,32736,0,T,NRJ.POMPES_BACHE.PUISSANCE_ELEC_INST,20190811T080000.000Z,20190811T194400.000Z
TR,NRJ.POMPES_BACHE.PUISSANCE_ELEC_INST,0,65535,1,1,,0,0,2
20190811T080000.000Z,0.00800000037997961,192
20190811T080100.000Z,0.008999999612569809,192
20190811T080200.000Z,0.008999999612569809,192
LB,32734,0,T,NRJ.POMPES_BACHE.PUISSANCE_ELEC_CPT,20190811T080000.000Z,20190811T201200.000Z
TR,NRJ.POMPES_BACHE.PUISSANCE_ELEC_CPT,0,65535,1,1,,0,0,2
20190811T080000.000Z,0.6743068099021912,192
20190811T080100.000Z,0.6744459867477417,192
20190811T080200.000Z,0.6745882630348206,192
20190811T080300.000Z,0.6747232675552368,192
20190811T080400.000Z,0.6748600006103516,192
20190811T080500.000Z,0.6749916672706604,192
20190811T080600.000Z,0.6751362681388855,192
1,2,3,4,5,6,7
1,2,3,4,5,7,7,8,9,10
1,2,3
1,2,3,4,5,6,7
1,2,3,4,5,7,7,8,9,10
1,2,3
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression