import Foundation
let pattern = #"([a-zA-Z]{3}\d{3})\s([a-zA-Z]{9}\s+\((\d{4})\)\s+\*[a-zA-Z]{3})\s+([a-zA-Z]+\d\w)\s+\.([a-zA-Z]+)\s(\d+)\s+"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
LMZ333 ALLOTMENT (0000) *TSC
HDQRM5I
.MADRIIB 160846
MADIB N4MPK/HELIB0150/1949417/HEL/IB/A/FI//RC//
HDQ5I N4MPK
1CUVILEON/CARLOS EDUARDO
1CONTRERASARNAEZ/MARIA BEGONA 1ROBLEDOCONTRERAS/PATRICIA
5I8397J/IB2198J25JUN RZGMAD CS1/0850 1220
5I8327J/IB2194J06JUL MADRZG CS1/1745 2115
OSI 5I CTCP 34606686051-M
OSI 5I POSI-DSAC//MADIB08AB/I/1
OSI 5I CARLOSCUVILIN//GMAIL.COM
=
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression