$re = '/(?<=.)[^@\n](?=[^@\n]*?[^@\n]@)|(?:(?<=@.)|(?!^)\G(?=[^@\n]*$)).(?=.*[^@\n]\.)/m';
$str = 'john.doe@example.en.com
foo@bar.com
foo-and.more!here@bar.com
fo@bar.com
f@bar.com';
$subst = "*";
$result = preg_replace($re, $subst, $str);
echo "The result of the substitution is ".$result;
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for PHP, please visit: http://php.net/manual/en/ref.pcre.php