using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = @"(?im)^(?=.{1,64}@)(?:(""[^""\\]*(?:\\.[^""\\]*)*""@)|((?:(?:\([^)]*\)|[^\W_])(?:\.(?!\.)|[-!#\$%&'\*\+\/=\?\^`\{\}\|~\w]|\([^)]*\))*)?[^\W_](?:\([^)]*\))?@))(?=.{1,255}$)(?:(\[[^\[\]]+\])|((?:(?=.{1,63}\.)[^\W_][-\w]*[^\W_]*\.)+[^\W_](?:[^\W_]|-){0,22}[^\W_])|((?=.{1,63}$)[^\W_][-\w]*))$";
string input = @"info@kamikaze.uk
alfred@live.nl
dubai@organon.it
karel.de.koning@hetnet.nl
decock@upc.nl
jiazhe_xu@sina.cn
xfunkblasterx@yahoomail.org
super-duper-email@hotmail.com
""John..Doe""@example.com
john.smith(comment)@example.com
(comment)john.smith@example.com
john.smith@worldwideweb.123com_org
""John.""(),:;<>@[\].Doe""@.123radio_tv
""much.more unusual""@example.com
other.email-with-dash@example.com
disposable.style.email.with+symbol@example.com
""()<>[]:,;@\\""!#$%&'-/=?^_`{}| ~.a""@example.org
smith@[IPv6:2001:db8::1]
jsmith@[192.168.2.1]";
foreach (Match m in Regex.Matches(input, pattern))
{
Console.WriteLine("'{0}' found at index {1}.", m.Value, m.Index);
}
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for C#, please visit: https://msdn.microsoft.com/en-us/library/system.text.regularexpressions.regex(v=vs.110).aspx