import Foundation
let pattern = #"Pass=([0-9]+).*classification_error_evaluator=(0\.[0-9]+).*classification_error_evaluator=(0\.[0-9]+)"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"I0419 01:52:16.606123 136 TrainerInternal.cpp:181] Pass=15 Batch=74 samples=3670 AvgCost=263.331 Eval: classification_error_evaluator=0.970178 I0419 01:52:16.815407 136 Tester.cpp:115] Test samples=458 cost=203.737 Eval: classification_error_evaluator=0.934446"#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression