# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"(?=\b\d{8}\b)(?:(?:9?8?7?6?5?4?3?2?1?0?)|(?:0?1?2?3?4?5?6?7?8?9?))(?<=\d{8})"
test_str = ("This regex is to match Ascending or descending order of 8 digit number\n"
"01234567 0 to 7\n"
"12345678 1 to 8\n"
"23456789 2 to 9\n"
"12456789 missing 3\n"
"01236789 missing 4,5\n"
"23456789 missing 0,1\n"
"1234567\n"
"12345\n"
"012345678\n"
"123456789\n"
"0123456789\n"
"98765432 9 to 2\n"
"87654321 8 to 1\n"
"76543210 7 to 0\n"
"98765321 missing 4\n"
"96543210 missing 7,8\n"
"98765432 missing 0,1\n\n\n\n")
matches = re.finditer(regex, test_str, re.MULTILINE)
for matchNum, match in enumerate(matches, start=1):
print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))
for groupNum in range(0, len(match.groups())):
groupNum = groupNum + 1
print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html