re = /^(?:.(?=.*\n(\1?.)))*?X.*\n\1?(.)/m
str = 'X.........
..........
...X......
..........
..X.......
..........
.......X..
..........
.........X
..........'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html