re = /\b0+\B/m
str = '092.01.001.220
192.16.092.000
02.1.001.01
010.064.214.210 
010.064.000.150 
010.000064.017.001 
127.00000.0.001 
10.0.00.000 
010.064.105.201'
subst = ''
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html