import Foundation
let pattern = #"DE\s+(3[01]|[12]\d|[1-9])\s+DE"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
DE 1 DE
DE 2 DE
DE 3 DE
DE 4 DE
DE 5 DE
DE 6 DE
DE 7 DE
DE 8 DE
DE 9 DE
DE 10 DE
DE 11 DE
DE 12 DE
DE 13 DE
DE 14 DE
DE 15 DE
DE 16 DE
DE 17 DE
DE 18 DE
DE 19 DE
DE 20 DE
DE 21 DE
DE 22 DE
DE 23 DE
DE 24 DE
DE 25 DE
DE 26 DE
DE 27 DE
DE 28 DE
DE 29 DE
DE 30 DE
DE 31 DE
DE 32 DE
DE 0 DE
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression