re = /^(\d{1}(?:\.\d{1,5})?|\d{2}(?:\.\d{1,4})?|100(?:\.0{1,3})?)$/m
str = '1
1.11
1.11111
1.11111111111
99
99.1
99.9999
99.99999
100
100.000
100.0000
100.001
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html