$re = '/",?/';
$str = '"2014", "2", "AMC-South", "inpatient", "complication", "1", "2", "2", "13,125.83", "6,562.95"
';
$subst = "";
$result = preg_replace($re, $subst, $str);
echo "The result of the substitution is ".$result;
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for PHP, please visit: http://php.net/manual/en/ref.pcre.php