re = /\d([0-9]{6})([0-9]{0,16})([0-9]{4})\d/
str = 'Aaaa bbbb aaa=1234567890123456 fdfdfd=aaa
Aaaa bbbb aaa=\\"1234567890123456\\" fdfdfd=aaa
Aaaa bbbb aaa=5155900762048745 fdfdfd=aaa'
subst = '$1******$3'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html