re = /\b0\d/m
str = '# bad
FOO=01
FOO=1,02,3
FOO=[1,02,3]
# good
FOO=1
FOO=[0,1,0,2,0,3]'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html