import Foundation
let pattern = #"(192.168.1.\d{1,3}).*?((\w{2}[:]){5}(\w{2}))"#
let regex = try! NSRegularExpression(pattern: pattern, options: [.anchorsMatchLines, .caseInsensitive, .dotMatchesLineSeparators])
let testString = #"""
{
"34:d2:70:87:42:68;": [
"192.168.1.81",
"\"amazon-8dee0891a\";"
],
"98:e0:d9:91:bc:71;": [
"192.168.1.32",
"\"Cathys-Air\";"
],
"88:71:e5:b3:cb:4e;": [
"192.168.1.172",
"\"amazon-205f4e28e\";"
],
"34:d2:70:7f:df:e7;": [
"192.168.1.76",
"\"amazon-8b38e6c4e\";"
],
"88:71:e5:a2:ff:66;": [
"192.168.1.77",
"\"amazon-43faa4ef3\";"
],
"b8:3e:59:f1:73:9f;": [
"192.168.1.190",
"\"Roku"
],
"18:b4:30:14:bc:da;": [
"192.168.1.179",
"\"02AA01AC42140DKR\";"
],
"ac:d1:b8:4d:a3:85;": [
"192.168.1.180",
"\"NPI4DA385\";"
],
"14:91:82:c9:8b:61;": [
"192.168.1.174",
"\"wemo\";"
],
"14:91:82:00:d5:35;": [
"192.168.1.184",
"\"wemo\";"
],
"08:00:27:89:03:db;": [
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression