import Foundation
let pattern = #"^http://127\.0\.0\.1:5000/countries(?:\?\w+=[\s\w]+(?:&\w+=[\s\w]+)*)?$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
http://127.0.0.1:5000/x
http://127.0.0.1:5000/countries?
http://127.0.0.1:5000/countries?x
http://127.0.0.1:5000/countries?=
http://127.0.0.1:5000/countries?x=
http://127.0.0.1:5000/countries&
http://127.0.0.1:5000/countries&x
http://127.0.0.1:5000/countries&=
http://127.0.0.1:5000/countries&x=
http://127.0.0.1:5000/countries&x=x
http://127.0.0.1:5000/countries?code=AU?
http://127.0.0.1:5000/countries?name=Australia?x
http://127.0.0.1:5000/countries?name=Australia?=
http://127.0.0.1:5000/countries?name=Australia?x=
http://127.0.0.1:5000/countries?name=Australia?x=x
http://127.0.0.1:5000/countries?name=Australia&
http://127.0.0.1:5000/countries?name=Australia&x
http://127.0.0.1:5000/countries?name=Australia&=
http://127.0.0.1:5000/countries?name=Australia&x=
http://127.0.0.1:5000/countries
http://127.0.0.1:5000/countries?name=Australia
http://127.0.0.1:5000/countries?code=AU&name=Australia
http://127.0.0.1:5000/countries?name=New Zealand&calling_code=64
http://127.0.0.1:5000/countries?code=AU&name=Australia&capital=Canberra
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression