re = /^(?:\d{4}|\d{6})$/m
str = '1
12
123
12345
1234567
-1234
1.234
-1.234
00000000
1234
0000
1111
123456
098765
000000
123456
090909
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html