re = /^interface\b.*(?:\r?\n(?!=).*)*/m
str = '======
interface And
public void and(int, int);
public void nand(int, int);
======
interface Or
public void or(int, int); public void nor(int, int);
======
interface Xor
public void xor(int, int); public void xnor(int, int);
======
interface Not
public void not(int);
======
class BitWise extends And, Or, Xor, Not
// Implementation of the Interfaces goes here
======
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html