re = /[a-zA-Z0-9,.'!-]+/
str = '20010db8 ~~ 0a0b:12f0:0000:0 000:0000:0001~!!!!!!!!5423462554&%^%*&%^^&%&^%&#$%@!@#!#!@%!^#$*^* fdsfdsfsdfsdasddsaas dQQWQWQWQWraerrewq rewr ew rewdasdFSD FSDF SDFSD FSD FSD FSD FSD ~~~@!#@#@fsdfsdf fds fds fsd fdsfsd f fsd fsd fsd fsd fsdfds'
subst = ''
result = str.sub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html