import Foundation
// WARNING: You included a flag that Swift doesn't support: u
// When this flag is set, it makes the pattern and subject strings to be treated as unicode.
// Swift already treats the pattern and subject strings as unicode by default, so including this flag is redundant.
let pattern = #"(?mi)(\d+)\.\h+(.+)(?:\R[a-e]\.\h+(.+))?(?:\R[a-e]\.\h+(.+))?(?:\R[a-e]\.\h+(.+))?(?:\R[a-e]\.\h+(.+))?(?:\R[a-e]\.\h+(.+))?\RAns:\h+(.+)"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
1. Question with 4 choices
a. one a
b. one b
c. one c
d. one d
Ans: B
23. True-False Question with no choices
Ans: T
2. Question with 3 choices
a. two a
b. two b
c. two c
Ans: C
3. Question with 2 choices
a. three a
b. three b
Ans: B
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression