using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = @"(84)2(38|7|96|54|09|04|91|16|06|75|15|18|7|9|3|56|5|71|74|90|14|9|13|36|6|61|8|63|51|77|0|69|19|73|97|93|4|6|39|5|8|37|59|34|1|60|1|05|70|35|55|08|03|59|76|10|57|11|07|33|99|94)(\d{7,8})";
string input = @"842926263007
842866598888
842072214668
842586504076
842736588235
842286544037
842466577226
842866739846
842156516668
842222210948
842106286816
842626338697
842086567555
842066562953
842606502439
842746294040
842462538003
842396542070
842422456111
";
RegexOptions options = RegexOptions.Multiline;
foreach (Match m in Regex.Matches(input, pattern, options))
{
Console.WriteLine("'{0}' found at index {1}.", m.Value, m.Index);
}
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for C#, please visit: https://msdn.microsoft.com/en-us/library/system.text.regularexpressions.regex(v=vs.110).aspx