re = /^(?!$)(?!0+$)\d{0,5}(?:\.(?!0{1,2}$)\d{1,2})?$/m
str = '12345.12
0.12
00000.0
00000
00000.01
00001
00000.00
00000.000
12345.89
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html