re = /^.* ((?:([12])|(3)|([45]))\d{4}) .*/m
str = 'Blah 12345 Blah
Blah 22345 Blah
Blah 32345 Blah
Blah 42345 Blah
Blah 52345 Blah'
subst = '(?2AAA:(?3BBB:XYZ))$1'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html