re = /\b0+/m
str = '20100327 15,18,37,39,44,52
20100328 02,08,24,31,33,50
20100330 16,26,27,39,40,46
20100522 05,07,10,11,13,27'
subst = ''
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html