re = /^(?!(?:[^\n\d]*\d){13})\d*[.]?\d{0,6}$/m
str = '1.22
1.234567
123456789012
1234567.9012
123456789012
1234567890123
1.2345678'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html