import Foundation
let pattern = #"^([a-f\d]{1,4}:){7}[a-f\d]{1,4}$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
1050:1000:1000:a000:5:600:300c:326b
1050:1000:2000:ab00:5:600:300c:326a
1050:1000:3000:abc0:5:600:300c:326c
1051:1000:4000:abcd:5:600:300c:326b
1050:0:0:0:5:600:300c:326b
1050:0:0:0:5:600:300c:326a
1050:0:0:0:5:600:300c:326c
1051:0:0:0:5:600:300c:326b
1050:10:0:0:5:600:300c:326b
1050:10:0:0:5:600:300c:326a
1050:10:0:0:5:600:300c:326c
1051:10:0:0:5:600:300c:326b
1050:10:0:0:15:600:300c:326b
1050:10:0:10:5:600:300c:326a
1050:10:10:0:5:600:300c:326c
1051:110:0:0:5:600:300c:326b
1050:10:0:0:15:600:300c:326k
1050:10:0:0:15:600:300c:326g
1050:10:0:0:15:600:300c:326h
1050:10:0:0:15:600:300c:326i
not an ip address
not an ipv4 Address
Not an IPv5 Address
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression