import re
regex = re.compile(r"if\s*(\((?>[^()]|(?1))*\))(*SKIP)(*F)|(\w+)(\s*<=[^;]*)", flags=re.DOTALL)
test_str = ("always @(posedge clk or negedge rst_n)\n"
"if(!rst_n)begin\n"
" d1 <= 0; //perl_comment_4\n"
" //perl_comment_5\n"
" d2 <= 1 //perl_comment_6\n"
" + 2;\n"
" end\n"
"else if( d3 <= d4 && ( d5 <= 3 ) ) begin\n"
" d6 <= d7 +\n"
" (d8 <= d9 ? 1 : 0);\n"
" //perl_comment_7\n"
" d10 <= d11 <=\n"
" d12\n"
" + d13\n"
" <= d14 ? 1 : 0;\n"
" end")
subst = "$2_yes$3"
result = regex.sub(subst, test_str)
if result:
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html