import Foundation
let pattern = #"([\d\(][\(\)\s\.\-\d]{4,}\d)"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
whatever 0 (000) 000-0000 whatever whatever 0(000)000-0000 whatever
whatever (000) 000-0000 whatever whatever (000)000-0000 whatever
whatever 000 000-0000 whatever whatever 000.000.0000 whatever
whatever 000-42000-0000 whatever whatever 000-0000 whatever
whatever 000 - 0000 whatever whatever 000.0000 whatever
whatever 000 . 0000 whatever whatever 000 0000 whatever 1
whatever 00000000000 whatever
whatever 0000000000 whatever
whatever 000000000 whatever
whatever 00000000 whatever
whatever 0000000 whatever
whatever 000000 whatever
whatever 00 00 0000 0000 whatever 3
whatever 00 0000 000 000 whatever 3
whatever 000 0000 0000 whatever 2
whatever (000) 0000 0000 whatever
whatever 00000 000000 whatever 1
whatever 00 0000 0000 whatever 21135
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression