re = /^(?:\+?1\h*)?(?:(\()?\d{3}(?(1)\))[-. ]?\d{3}[-. ]?\d{4})$/m
str = '589-845-2889
(589)-845-2889
589.845.2889
589 845 2889
5898452889
(589) 845 2889
1(589) 845 2889
+1(589) 845 2889
1589 845 2889
1 589 845 2889
15898452889
+1207 244 7002
+1 207 244 7002
(589) 845-2889
+1(589) 845-2889
1(589) 845-2889'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html