import Foundation
let pattern = #"(?<![a-z'-] )([A-Z][a-z'-]++)[^(A-Z]*\(([^)]+)\)[^A-Z\v]+([A-Z][a-z'-]++)(?!\s[A-Z])[^(A-Z]*\(([^)]+)\)"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
[Nisei](slightly scratched) [Ocellaris](unconcious)
L: 1799 Ocellaris: (slightly scratched) vs. N'isei: (mildly wounded)
[Nisei](slightly scratched) [Zealot Warrior](perfect condition)
L: 1799 Ocellaris: (slightly scratched) vs. zealot warrior: (mildly wounded)
[fire dragon](slightly scratched) [Zealot Warrior](perfect condition)
[King Jheric](slightly scratched) [Zealot Warrior](perfect condition)
Me:(condition) v Target:(condition)
Reply:Some Person L:1200 King Jheric:(condition) vs. Target:(condition)
[Me] -> (condition) [wolfen berserker] -> (condition)
Lag: 1200 [zealot warrior](condition) vs. [King Jheric](condition)
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression