import Foundation
let pattern = #"^((25[0-5]|2[0-4]\d|[01]?\d{1,2})\.){3}(25[0-5]|2[0-4]\d|[01]?\d{1,2})$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
22.231.113.64
22.231.113.164
222.231.113.64
22.231.113.64
22.231.113.164
255.231.111.64
253.231.111.64
22.21.113.61
22.21.113.162
255.21.111.63
253.21.111.69
22.211.113.64
22.212.113.164
255.213.111.64
253.214.111.64
22.211.113.364
22.212.113.3164
255.213.111.464
253.214.111.564
not an ip address
not an ipv4 Address
Not an IPv5 Address
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression