re = /0?(?:[1-9]|1[0-2])\/0?(?:[1-9]|12[0-9]|3[01])\/1\d{3}/m
str = '12/10/2021
1/1/1990
01/08/1937
15/36/1718
3/33/1999
1/2/2000
12/9/1906
13/31/1999'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html