import Foundation
let pattern = #"^[+]?([0-9]*[\.\s\-\(\)]|[0-9]+){3,24}$"#
let regex = try! NSRegularExpression(pattern: pattern, options: [.anchorsMatchLines, .caseInsensitive])
let testString = #"""
011 (416) 457 7845
+1 (416) 457 7845
011416457111
Standard Telephone numbers
+61 1 2345 6789
+61 01 2345 6789 (zero entered is not required but enterd by user anyway)
01 2345 6789
01-2345-6789
(01) 2345 6789
(01) 2345-6789
1234 5678
1234-5678
12345678
^(\+[1-9][0-9]*(\([0-9]*\)|-[0-9]*-))?[0]?[1-9][0-9\- ]*$
^(\+[1-9][0-9]*(\([0-9]*\)|-[0-9]*-))?[0]?[1-9][0-9\- ]*$
^\+([0-9]( |-|\+)?)?(\(?[0-9]{3}\)?|[0-9]{3})( |-)?([0-9]{3}( |-)?[0-9]{4}|[a-zA-Z0-9]{7})$
^((\\+[1-9]{1,4}[ \\-]*)|(\\([0-9]{2,3}\\)[ \\-]*)|([0-9]{2,4})[ \\-]*)*?[0-9]{3,4}?[ \\-]*[0-9]{3,4}?$
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression