import re
regex = re.compile(r"(my date of birth is|my birthdate is|my birthday is|my bday is|i was born on|date of birth is|dob is|birthdate is|my dob is|birthday|birth date is)*(\s)*(((0)[0-9])|((1)[0-2])|(January|Jan|February|Feb|March|Mar|April|Apr|May|June|Jun|July|Jul|August|Aug|September|Sep|October|Oct|November|Nov|December|Dec))(\/|.|-)([0-2][0-9]|(3)[0-1])(\/|.|-)\d{2,4}", flags=re.IGNORECASE)
test_str = ("1. dob is 12-19-1994\n"
"2. 1234\n"
"3. 4567\n"
"4. 09/19/1993\n"
"5. Mar 14 1954\n"
"6. asd \n"
"7. dob is 12-12-1234\n"
"8. 4456\n"
"9. 352345\n"
"12345678\n"
"09-19-1993\n"
"09.19.1993\n"
"\"09.19.1993\"\n"
"january 10 2021\n"
"09191993")
subst = "$1"
result = regex.sub(subst, test_str)
if result:
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html