re = /^i=\d+(?:&s\d+=\d+)+$/
str = 'i=1&s1=122&s2=238&s3=167&s4=756&s5=13'
# Print the match result
str.match(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html