re = /.*(\d{4})/m
str = 'ABC123456789A9876
ABCD1234567890F23
1234ABC4567JIJLMN
ABCDEFG1234-!.567
12345660703J1A501F4Z2051
1234ABCLDlZd1523
1234ABCLDlZd15
ABC1234
ABC1234ABC1234A
ABC123ABC123A'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html