re = /^(\d{2})(\s?)(9?\d{4})(-?)\d{4}/m
str = '11 8765-1234
11 98765-1234
118765-1234
11 87651234
11987651234
119876512345 = muitos números não validaria
11876541234 = muitos números sem o 9 também não validaria.
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html