import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main(String[] args) {
final String regex = "^.*[^\\d\\r\\n](\\d+)";
final String string = "2^64\n"
+ "asdgaf1_hsg534\n"
+ "asdfh23_hsjd12\n"
+ "dgshg_jhfsd86\n"
+ "test\n"
+ "1\n"
+ "testing 1234 testing 1 test4\n"
+ "testing 1234 testing 123";
final String subst = "\\1";
final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
final Matcher matcher = pattern.matcher(string);
// The substituted value will be contained in the result variable
final String result = matcher.replaceAll(subst);
System.out.println("Substitution result: " + result);
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Java, please visit: https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html