re = /(\p{Lu}\w+)=(\s?[.\s@\w\-]+)/
str = 'Dec 17 10:08:38 10.52.137.1 Apr 3 22:46:57 2012 930|RTR-944 %%10SC/6/SC_AAA_LAUNCH(l): |DevIP=10.52.137.1|AAAType=AUTHEN|AAAScheme= hwtacacs-scheme tacacs|Service=login|UserName=monitor@system; AAA launched.
DevIP=10.52.137.1|AAAType=AUTHEN|AAAScheme= hwtacacs-scheme tacacs|Service=login|UserName=monitor@system'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html