re = /^(?=\d?(\d\d)\1{3})\d{9}$/m
str = '561616161
121212123
411111111
111111114
111111111
299887766
887756564
123412345
123123123
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html